Back to FAQs
Related FAQs

Frequently Asked Question

Questions asked by users might not always be phrased in the clearest way.

0.2688-g sample of a monoprotic acid neutralizes 16.4 ml of 0.08133 m KOH solution. Calculate the molar mass of the acid.

Accepted Answer

Here's how to calculate the molar mass of the acid:
1. Calculate moles of KOH:

moles KOH = (volume in L)
(concentration in mol/L)

moles KOH = (0.0164 L)
(0.08133 mol/L) = 0.00133 mol
2. Determine moles of acid:

Since the acid is monoprotic (donates one H+), it reacts in a 1:1 ratio with KOH.

Therefore, moles of acid = moles of KOH = 0.00133 mol
3. Calculate molar mass of acid:

molar mass = (mass of acid) / (moles of acid)

molar mass = (0.2688 g) / (0.00133 mol) = 202 g/mol
Therefore, the molar mass of the monoprotic acid is 202 g/mol.

Articles you might like

Discover more articles
🚀 Welcome to TheAiWay! ChemistAI has evolved into TheAiWay.org, offering faster speeds, expanded AI-powered content across 32 subjects, and a brand-new, user-friendly design. Enjoy enhanced stability, increased query limits (30 to 100), and even unlimited features! Discover TheAiWay.org today! ×