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0.45 gm of an acid with molecular mass 90 g/mole is neutralization by 20 ml of 0.5 n caustic potash(koh). The basicity of the acid is:rn(a)rn1rn(b)rn2rn(c) 3rn[2 M]rn(D)rn4
Accepted Answer
The correct answer is B: 2
Explanation:
1. Calculate the millimoles of KOH used:
mmolofKOH = (Volume of KOH in mL) × (Normality of KOH in N)
mmolofKOH = (20 mL) × (0.5 N) = 10 mmol
2. Since the reaction between the acid and KOH is a neutralization reaction, the millimoles of acid used will be equal to the millimoles of KOH used:
mmolofacid = 10 mmol
3. Calculate the molar mass of the acid:
molar mass of acid = (Mass of acid in g) / (Millimoles of acid)
molar mass of acid = (0.45 g) / (10 mmol) = 90 g/mol
4. The basicity of an acid is the number of replaceable hydrogen ions (H+) per molecule of the acid. In this case, the acid has a molecular mass of 90 g/mol, which means it has a molar mass of 90 g/mol. Since the acid is neutralized by 10 mmol of KOH, each molecule of the acid must have 2 replaceable hydrogen ions. Therefore, the basicity of the acid is 2.
Explanation:
1. Calculate the millimoles of KOH used:
mmolofKOH = (Volume of KOH in mL) × (Normality of KOH in N)
mmolofKOH = (20 mL) × (0.5 N) = 10 mmol
2. Since the reaction between the acid and KOH is a neutralization reaction, the millimoles of acid used will be equal to the millimoles of KOH used:
mmolofacid = 10 mmol
3. Calculate the molar mass of the acid:
molar mass of acid = (Mass of acid in g) / (Millimoles of acid)
molar mass of acid = (0.45 g) / (10 mmol) = 90 g/mol
4. The basicity of an acid is the number of replaceable hydrogen ions (H+) per molecule of the acid. In this case, the acid has a molecular mass of 90 g/mol, which means it has a molar mass of 90 g/mol. Since the acid is neutralized by 10 mmol of KOH, each molecule of the acid must have 2 replaceable hydrogen ions. Therefore, the basicity of the acid is 2.
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