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1.rnif the work function of a metal is 6.63×10-19j, the maximum wavelength of the photon required to remove a photoelectron from the metal is nm. [given: h = 6.63×10-34 js and c=3×108 ms 1]rn[1.5 min]rn(a)rn300rn(b)rn30rn(c)rn0.3rn(d)rn3×103
Accepted Answer
The correct answer is (C) 0.3
Explanation:
Work function (W) = 6.63×10-19 J
Planck's constant (h) = 6.63×10-34 Js
Speed of light (c) = 3×108 ms-1
Maximum wavelength (λ) = hc/W
= (6.63×10-34 Js × 3×108 ms-1) / 6.63×10-19 J
= 3×10-7 m
= 300 nm
Therefore, the maximum wavelength of the photon required to remove a photoelectron from the metal is 300 nm.
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