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2. Fe(phen)2(SCN)2 has an effective magnetic moment of ~5.5 B.M. at 300 k and ~0.90 B.M. at 150 k. Explain this difference in magnetic moments and comment on any differences in the electronic spectra at the two temperatures

Accepted Answer

The observed change in magnetic moment of Fe(phen)2(SCN)2 with temperature suggests a spin-crossover phenomenon. At higher temperatures (300 K), the iron(II) ion is likely in a high-spin state (S=2) with four unpaired electrons, leading to a magnetic moment of ~5.5 B.M. As the temperature decreases to 150 K, the iron(II) ion transitions to a low-spin state (S=0) with no unpaired electrons, resulting in a much lower magnetic moment of ~0.90 B.M. This transition is driven by the energy difference between the high-spin and low-spin states, which is influenced by the ligand field strength and temperature.
In terms of the electronic spectra, at 300 K, the high-spin state would exhibit a weaker ligand field, leading to lower energy d-d transitions and potentially a broader, less intense absorption band. At 150 K, the low-spin state would exhibit a stronger ligand field, resulting in higher energy d-d transitions and potentially a narrower, more intense absorption band. However, specific spectral changes would depend on the individual electronic transitions involved.
This behavior is typical of certain transition metal complexes with labile coordination environments and a delicate balance between ligand field strength and temperature.


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