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2-propanol reacts with iodine in aqueous solution of NaOH to produce light yellow precipitate but compound Qdoes not. Explain the observation
Accepted Answer
2-propanol is a secondary alcohol and undergoes oxidation in the presence of strong oxidizing agents such as iodine in an alkaline medium to form a yellow precipitate of iodoform. Compound Q, if it is a primary alcohol or does not have a methyl group attached to the carbon bearing the -OH group, will not undergo this reaction and no precipitate will be formed.
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