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2al(oh)3 +3h2so4 = Al2(SO4)3 + 6h2o how many moles of Al2(SO4)3 can form under these conditions? (c) how many moles of the excess reactant remain after the completion of the reaction?
Accepted Answer
To answer this, we need the starting moles of both reactants, Al(OH)3 and H2SO4. The balanced equation shows the mole ratio: 2 moles Al(OH)3 react with 3 moles H2SO4 to produce 1 mole Al2(SO4)3. Please provide the moles of each reactant to calculate the moles of Al2(SO4)3 formed and the excess reactant remaining.
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