Frequently Asked Question

Questions asked by users might not always be phrased in the clearest way.

3.39 Cinnamic alcohol is used mainly in perfumery, particularly in soaps and cosmetics. Its molecular formula is CH100. (a) Calculate the percent composition by mass of c, h, and o in cinnamic alcohol. (b) How many molecules of cinnamic alcohol are contained in a sample of mass 0.469 g?

Accepted Answer

Here's how to calculate the percent composition and the number of molecules in cinnamic alcohol:
(a) Percent Composition by Mass
1. Find the molar mass:

C: 12.01 g/mol
9 = 108.09 g/mol

H: 1.01 g/mol
10 = 10.10 g/mol

O: 16.00 g/mol
1 = 16.00 g/mol

Total Molar Mass = 108.09 + 10.10 + 16.00 = 134.19 g/mol
2. Calculate the percent composition for each element:

% C = (108.09 g/mol / 134.19 g/mol)
100% = 80.56%

% H = (10.10 g/mol / 134.19 g/mol)
100% = 7.55%

% O = (16.00 g/mol / 134.19 g/mol)
100% = 11.91%
(b) Number of Molecules
1. Convert grams to moles:

Moles = mass (g) / molar mass (g/mol)

Moles = 0.469 g / 134.19 g/mol = 0.00350 mol
2. Use Avogadro's number to find the number of molecules:

Number of molecules = moles
Avogadro's number (6.022 x 10^23 molecules/mol)

Number of molecules = 0.00350 mol
6.022 x 10^23 molecules/mol = 2.11 x 10^21 molecules


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