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Questions asked by users might not always be phrased in the clearest way.
Here's the breakdown:
a. Molar mass of calcium carbonate (CaCO3):
Calcium (Ca): 40.08 g/mol
Carbon (C): 12.01 g/mol
Oxygen (O): 16.00 g/mol (x 3 = 48.00 g/mol)
Total molar mass: 40.08 + 12.01 + 48.00 = 100.09 g/mol
b. Mass of 4.86 moles of calcium carbonate:
Mass = moles x molar mass
Mass = 4.86 mol x 100.09 g/mol = 486.44 g
c. Mass of CO3^2- ions present:
First, calculate the mass of one mole of CO3^2- ions:
Carbon (C): 12.01 g/mol
Oxygen (O): 16.00 g/mol (x 3 = 48.00 g/mol)
Total mass: 12.01 + 48.00 = 60.01 g/mol
Since there's one mole of CO3^2- ions in one mole of CaCO3, the mass of CO3^2- ions in the sample is also 60.01 g/mol.