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4. explain the relative solubility of sodium chloride in a) water and b) hexane by looking at the particles present in sodium chloride and the forces of attraction holding particles together.
Accepted Answer
Sodium chloride (NaCl) dissolves readily in water due to the strong electrostatic interactions between its ions (Na+ and Cl-) and the polar water molecules. Water molecules, with their partial positive and negative charges, surround and interact with the ions, effectively breaking the ionic bonds in the NaCl crystal lattice and allowing the ions to dissolve.
In contrast, hexane is a nonpolar solvent. It lacks the ability to form strong attractions with the charged ions of sodium chloride. As a result, sodium chloride remains undissolved in hexane.
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