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A 0.02 m solution of KOH would have a ph of

Accepted Answer

The pH of a 0.02 M solution of KOH can be calculated using the formula pH = 14 - pOH, where pOH = -log[OH-]. The concentration of OH- in a 0.02 M solution of KOH is 0.02 M, so the pOH is -log(0.02) = 1.699. Therefore, the pH of the solution is 14 - 1.699 = 12.301.

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