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A 43.0 ml of sodium hydroxide was titrated against 32.0 ml of 0.100 m hydrochloric acid. What is the molarity of sodium hydroxide solution?rnrn1. Compute for the number of moles of HCIrnrn2. Compute for the moles of NaOHrnrn3. Compute for the Molarity of NaOH.

Accepted Answer

1. Compute for the number of moles of HCl





Moles of HCl = Molarity x Volume

Moles of HCl = 0.100 M x 0.0320 L

Moles of HCl = 0.00320 mol





2. Compute for the moles of NaOH





Because the reaction between HCl and NaOH is 1:1, the moles of NaOH are equal to the moles of HCl.

Moles of NaOH = 0.00320 mol





3. Compute for the Molarity of NaOH





Molarity of NaOH = Moles of NaOH / Volume of NaOH

Molarity of NaOH = 0.00320 mol / 0.0430 L

Molarity of NaOH = 0.0744 M





Therefore, the molarity of the sodium hydroxide solution is 0.0744 M.

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