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A compound contains 40.8 g of carbon and 259 g of fluorine. What is the empirical formula for this compound?
Accepted Answer
To find the empirical formula, we need to determine the mole ratio of carbon to fluorine. Here's how:
1. Convert grams to moles:
Moles of Carbon (C): 40.8 g / 12.01 g/mol = 3.40 mol
Moles of Fluorine (F): 259 g / 19.00 g/mol = 13.6 mol
2. Determine the mole ratio:
Divide both mole values by the smaller value (3.40 mol):
C: 3.40 mol / 3.40 mol = 1
F: 13.6 mol / 3.40 mol = 4
3. Empirical Formula:
The empirical formula is CF₄
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