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A is a SOLUTION KMN04 containing 0.02mol/dm3 and b is a solution of KCl. Put a unto the burette and titrate with 25cm of B b. State the Indicator of the above c.state the ionic equation of relation d from result and Information. cakcy i. Con b in mol/dm³ ii. Conc a in g/dm³ iii.conc b in g/dm³ iv Amount of a in titre valve v Amount of b in 25 cm³
Accepted Answer
This query involves chemistry concepts like titration and solution concentrations. Here's a breakdown of the information and how to approach the calculations:
a. Titration Setup:
You're titrating a potassium permanganate (KMnO₄) solution (A) with potassium chloride (KCl) solution (B).
b. Indicator:
Potassium permanganate acts as its own indicator. The solution is colorless until the endpoint, when it turns a faint pink color due to excess MnO₄⁻ ions.
c. Ionic Equation:
The reaction between KMnO₄ and KCl is unlikely to occur as it's a double displacement reaction with no precipitate formation. Titration usually involves a redox reaction, not a simple double displacement. To write an ionic equation, we'd need a redox reaction.
d. Calculations:
i. Concentration of B (KCl) in mol/dm³:
You need the volume of A used in the titration and the stoichiometry of the reaction to calculate the concentration of B. Provide the volume of A, and we can determine the concentration of B.
ii. Concentration of A (KMnO₄) in g/dm³:
You're given the concentration of A as 0.02 mol/dm³. To convert this to g/dm³, you need the molar mass of KMnO₄.
Molar mass of KMnO₄ ≈ 158 g/mol
Concentration of A in g/dm³ = (0.02 mol/dm³)
(158 g/mol) ≈ 3.16 g/dm³
iii. Concentration of B (KCl) in g/dm³:
Similar to calculating the concentration of A in g/dm³, we need the molar mass of KCl and the concentration of B in mol/dm³ (which we'll determine from the titration data).
Molar mass of KCl ≈ 74.55 g/mol
iv. Amount of A in the titre valve:
This requires the volume of A used in the titration. With that volume and the concentration of A (0.02 mol/dm³), you can calculate the amount of A in moles.
v. Amount of B in 25 cm³:
To calculate this, we need the concentration of B in mol/dm³ (determined from the titration data). Then, we can use the volume (25 cm³) to calculate the amount of B in moles.
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