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A lead storage battery was discharged to flow 0.4 mol of electrons. Find the change of the mass of cathode.
Accepted Answer
The change in mass of the cathode can be calculated using Faraday's law of electrolysis. The equation is: m = (M * I * t) / (z * F)
m = mass of the cathode (in grams)
M = molar mass of the cathode (in grams per mole)
I = current (in amperes)
t = time (in seconds)
z = number of electrons transferred per ion
F = Faraday's constant (96,485 coulombs per mole)
In this case, we have:
M = 207.2 g/mol (molar mass of lead)
I = 0.4 mol * 96,485 C/mol = 38,594 C
t = time (not given in the question)
z = 2 (lead ions have a charge of +2)
F = 96,485 C/mol
We need to rearrange the equation to solve for t:
t = (m * z * F) / (M * I)
t = (m * 2 * 96,485 C/mol) / (207.2 g/mol * 38,594 C)
t = 0.0252 m
Therefore, the change in mass of the cathode is 0.0252 grams.
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