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Sure. Here is the equilibrium constant expression and the equilibrium constant for the reaction:
$$ text{CO} + text{Cl}_2 rightleftharpoons text{COCl}_2 $$
$$ K_C = frac{[text{COCl}_2]}{[text{CO}][text{Cl}_2]} = frac{0.330^2}{(0.967)(0.967)} = 0.108 $$
Therefore, at 600 degrees C, the equilibrium constant for this reaction is 0.108.