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Questions asked by users might not always be phrased in the clearest way.
A reasonable man in Black Rock came upon a plastic container with a purple powder. The label on the bottle indicated [co(ox)3}^4-. he brings it to the lab and asks you to investigate the degree of magnetism. (b) which theoretical magnetic moment would you use to calculate the magnetic moment? The Spin only magnetic moment or the S+L magnetic moment?
Accepted Answer
The complex ion [Co(ox)3]^4- has a cobalt(II) ion (Co^2+) in a low-spin configuration.
To determine the magnetic moment, you should use the Spin-only magnetic moment because the cobalt(II) ion in this complex is a d^7 ion in an octahedral field, which results in a low-spin configuration with all the electrons paired up.
The formula for spin-only magnetic moment is:
μs = √n(n+2) BM, where n is the number of unpaired electrons.
Since all electrons are paired, n = 0. Therefore, the spin-only magnetic moment will be 0 BM (Bohr magnetons).
The S+L magnetic moment considers both spin and orbital angular momentum and is typically used for high-spin complexes where there are unpaired electrons. However, it is not applicable to this low-spin complex.
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