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A sample of Oxygen gas occupies 257 ml at 20 degrees Celsius and 1.2 atm. What is the 2 volume of this Oxygen gas sample at STP?

Accepted Answer

PV=nRT

At constant number of moles of oxygen gas, we have:

P1V1T2=P2V2T1

Inserting values:

(1.2 atm)(257 mL)T2=(1 atm)(V2)(273K)

T2=222.5 K

Thus, the volume of oxygen gas at STP will be:

V2=(P1V1T2)/(P2T1)

=(1.2atm)(257mL)(273K)/(1atm)(222.5K)

=307.5mL


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