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This is a classic example of Gay-Lussac's Law, which states that the pressure of a gas is directly proportional to its absolute temperature when the volume and amount of gas are held constant. Here's how to solve it:
1. Convert Temperatures to Kelvin:
Initial temperature (T1): 23°C + 273.15 = 296.15 K
Final temperature (T2): 475°C + 273.15 = 748.15 K
2. Apply Gay-Lussac's Law:
P1/T1 = P2/T2
P2 = (P1
T2) / T1
P2 = (1344 torr
748.15 K) / 296.15 K
P2 ≈ 3400 torr
Therefore, the pressure in the hot can will be approximately 3,400 torr.