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To determine the ground state energy term for [Co(ox)3]4-, we need to consider the electronic configuration and the spin state of the cobalt(II) ion.
1. Electronic Configuration: Cobalt(II) has a d7 electronic configuration. In the complex, the oxalate ligands (ox) are strong field ligands, causing significant splitting of the d orbitals. This leads to the low spin configuration, where all seven electrons occupy the lower energy d orbitals.
2. Spin State: With seven electrons in the lower energy d orbitals, the complex has three unpaired electrons. This results in a spin multiplicity of 2S+1 = 4, meaning it is a quartet state.
3. Ground State Term Symbol: The ground state term symbol is determined by the total orbital angular momentum (L) and the total spin angular momentum (S). For a d7 configuration in a low spin complex, L = 2 and S = 3/2. Therefore, the ground state term symbol is 4F.
This indicates that the complex is paramagnetic, with three unpaired electrons contributing to its magnetic moment.