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An aqueous solution of 12.6 g oxalic acid dihydrate is made upto 250 ml. The volume (in ml) of 1.0 n NaOH required to completely neutralize 10 ml of this solution is
Accepted Answer
Calculate the moles of oxalic acid in 10 mL of the solution
12.6 g oxalic acid dihydrate = 12.6 g * (1 mol / 126.07 g/mol) = 0.1 mol
0.1 mol / 250 mL * 10 mL = 0.004 mol
Calculate the volume of 1.0 N NaOH required to neutralize 0.004 mol of oxalic acid
0.004 mol oxalic acid * (2 mol NaOH / 1 mol oxalic acid) * (1 L NaOH / 1 mol NaOH) * (1000 mL / 1 L) = 8 mL
12.6 g oxalic acid dihydrate = 12.6 g * (1 mol / 126.07 g/mol) = 0.1 mol
0.1 mol / 250 mL * 10 mL = 0.004 mol
Calculate the volume of 1.0 N NaOH required to neutralize 0.004 mol of oxalic acid
0.004 mol oxalic acid * (2 mol NaOH / 1 mol oxalic acid) * (1 L NaOH / 1 mol NaOH) * (1000 mL / 1 L) = 8 mL
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