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An object at 289^0 k has a density of 4.10 g/cm^3 and a volume of 26,112 cm^3.rnwhich and choice represents BOTH the correct temperature of the object in Fahrenheit AND the correct mass of the object in kg?rn15.9 °f; 1.07 × 10² kgrn60.5 °f; 1.07 × 10² kgrn562 ° f; 1.07 × 10 ‐⁵rn60.5 ° f; 1.07 × 10⁵ kg
Accepted Answer
Here's how to find the correct temperature and mass:
Temperature Conversion:
- Convert Kelvin to Celsius: °C = K - 273.15
- Convert Celsius to Fahrenheit: °F = (°C
9/5) + 32
Mass Calculation:
- Density = Mass/Volume
- Mass = Density
Volume
Let's calculate:
1. Temperature:
- °C = 289 K - 273.15 = 15.85 °C
- °F = (15.85 °C
9/5) + 32 ≈ 60.5 °F
2. Mass:
- Mass = 4.10 g/cm³
26,112 cm³ = 107,232 g
- Convert grams to kilograms: 107,232 g
(1 kg/1000 g) = 107.232 kg ≈ 1.07 × 10² kg
Therefore, the correct answer is 60.5 °F; 1.07 × 10² kg
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