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Apply vbt on BCl3
Accepted Answer
Boron trichloride (BCl3) has a trigonal planar geometry with bond angles of 120°. According to Valence Bond Theory (VBT), boron's 2s and 2p orbitals hybridize to form three sp² orbitals, which are oriented at 120° angles. These sp² orbitals then overlap with the 3p orbitals of the three chlorine atoms, forming three sigma bonds. The remaining unhybridized 2p orbital on boron remains empty. This explains the trigonal planar shape and the absence of a dipole moment in BCl3.
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