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Aqueous hydrobromic acid reacts with solid sodium hydroxide to produce aqueous sodium bromide and liquid water . What is the theoretical yield of water formed from the reaction of 4.9 g of hydrobromic acid and 1.9 g of sodium hydroxide?rnrnround your answer to 3 significant figures.
Accepted Answer
The balanced chemical equation for the reaction is:
2 HBr(aq) + 2 NaOH(s) → 2 NaBr(aq) + 2 H2O(l)
From the equation, we can see that 2 moles of HBr react with 2 moles of NaOH to produce 2 moles of H2O.
To determine the theoretical yield of water, we need to first convert the given masses of HBr and NaOH to moles:
moles of HBr = 4.9 g / 80.91 g/mol = 0.0606 mol
moles of NaOH = 1.9 g / 40.00 g/mol = 0.0475 mol
Since NaOH is the limiting reactant (it has fewer moles than HBr), the theoretical yield of water will be based on the number of moles of NaOH.
moles of H2O produced = 0.0475 mol NaOH × (2 mol H2O / 2 mol NaOH) = 0.0475 mol H2O
Finally, we convert the moles of H2O to grams:
mass of H2O = 0.0475 mol × 18.02 g/mol = 0.855 g
Therefore, the theoretical yield of water formed from the reaction of 4.9 g of hydrobromic acid and 1.9 g of sodium hydroxide is 0.855 g.
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