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Aqueous hydrochloric acid reacts with solid sodium hydroxide to produce aqueous sodium chloride and liquid water . if 2.79 g of sodium chloride is produced from the reaction of 2.2 g of hydrochloric acid and 3.3 g of sodium hydroxide, calculate the percent yield of sodium chloride. round your answer to 2 significant figures. What is the percent yield?
Accepted Answer
Here's how to calculate the percent yield:
1. Write the balanced chemical equation:
HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l)
2. Calculate the theoretical yield of NaCl:
Find the limiting reactant:
Convert grams of HCl to moles of HCl: 2.2 g HCl
(1 mol HCl / 36.46 g HCl) = 0.060 mol HCl
Convert grams of NaOH to moles of NaOH: 3.3 g NaOH
(1 mol NaOH / 40.00 g NaOH) = 0.0825 mol NaOH
Since the mole ratio of HCl to NaOH is 1:1, HCl is the limiting reactant because it has fewer moles.
Use the limiting reactant (HCl) to calculate the theoretical yield of NaCl:
0.060 mol HCl
(1 mol NaCl / 1 mol HCl)
(58.44 g NaCl / 1 mol NaCl) = 3.51 g NaCl
3. Calculate the percent yield:
Percent yield = (actual yield / theoretical yield)
100%
Percent yield = (2.79 g NaCl / 3.51 g NaCl)
100% = 79.5%
Therefore, the percent yield of sodium chloride is 79%.
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