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Balance the following: AlCl3 -> al + Cl2rnrnIf 10.0 g of aluminum chloride are decomposed, how many molecules of Cl2 are produced?

Accepted Answer

Balanced equation:

> 2AlCl3 → 2Al + 3Cl2

10.0 g AlCl3 x (1 mol AlCl3/133.34 g/mol AlCl3) x (3 mol Cl2/ 2 mol AlCl3) x (6.022 x 10^23 molecules Cl2/ 1 mol Cl2) = 2.67 x 10^23 molecules Cl2

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