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Butanoic acid is an example of an organic acid. if it dissolves in aqueous solutions,rndetermine its initial concentration, given the concentration hydronium ion at equilibrium rnto be 1.2×10-7 m and ka to be 1.5×10-5
Accepted Answer
The initial concentration of butanoic acid can be calculated using the expression for the acid dissociation constant (Ka) and the equilibrium concentration of hydronium ions ([H3O+]).
Ka = [H3O+][A-] / [HA]
where [A-] is the concentration of the conjugate base (butanoate ion) and [HA] is the concentration of the weak acid (butanoic acid).
At equilibrium, we have:
Ka = (1.2 × 10^-7)^2 / [HA]
Solving for [HA], we get:
[HA] = (1.2 × 10^-7)^2 / 1.5 × 10^-5 = 9.6 × 10^-4 M
Therefore, the initial concentration of butanoic acid is 9.6 × 10^-4 M.
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