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Calculate [co(ox)3]4- theoretical magnetic moment
Accepted Answer
To calculate the theoretical magnetic moment of [Co(ox)₃]⁴⁻, we need to consider the following:
1. Oxidation State of Cobalt: In this complex, cobalt exists as Co²⁺.
2. Electronic Configuration of Co²⁺: The electronic configuration of Co²⁺ is [Ar] 3d⁷.
3. Ligand Field Splitting: Oxalate (ox) is a weak field ligand, leading to a high-spin configuration in Co²⁺.
4. Number of Unpaired Electrons: In a high-spin configuration, Co²⁺ will have 3 unpaired electrons.
5. Spin-Only Magnetic Moment Formula: μ = √n(n+2) BM, where n is the number of unpaired electrons and BM is the Bohr magneton.
Calculation:
μ = √3(3+2) BM = √15 BM ≈ 3.87 BM
Therefore, the theoretical magnetic moment of [Co(ox)₃]⁴⁻ is approximately 3.87 Bohr magnetons.
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