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CH2=CH2+H2O->CH3-CH2-OH What's the change of enthalpy in kj/mol
Accepted Answer
The reaction you provided is the hydration of ethene (CH2=CH2) to form ethanol (CH3-CH2-OH). To determine the change in enthalpy (ΔH) for this reaction, you'd need to look up the standard enthalpy of formation for each compound involved. The change in enthalpy can be calculated using the following equation: ΔH = ΣΔHf(products) - ΣΔHf(reactants). Remember that the standard enthalpy of formation for elements in their standard state is 0 kJ/mol.
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