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Deduce the relationship between kp and kc for the gaseous equilibria; (i) $2no_{(g)}+o_{2}(g)rightarrow 2no_{2}(g)$ (5 marks)

Accepted Answer

The relationship between Kp and Kc for the given gaseous equilibrium can be deduced using the following equation:
Kp = Kc(RT)^Δn
Where:
Kp is the equilibrium constant in terms of partial pressures.
Kc is the equilibrium constant in terms of molar concentrations.
R is the ideal gas constant (0.0821 L atm/mol K).
T is the temperature in Kelvin.
Δn is the change in the number of moles of gas in the balanced chemical equation (moles of products - moles of reactants).
For the reaction:
2NO(g) + O2(g) ⇌ 2NO2(g)
Δn = (2) - (2 + 1) = -1
Therefore, the relationship between Kp and Kc is:
Kp = Kc(RT)^-1
Kp = Kc/(RT)


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