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Determime the diamagnetic correction calculation for ueff of [co(ox)3]4-?
Accepted Answer
The diamagnetic correction for the effective magnetic moment (μeff) of [Co(ox)3]4- is calculated using the following steps:
1. Determine the oxidation state of the metal ion: Cobalt in [Co(ox)3]4- has an oxidation state of +2.
2. Determine the number of unpaired electrons: Cobalt(II) has 3d7 electronic configuration, and in an octahedral complex, the electrons occupy the d orbitals in a specific order. The complex [Co(ox)3]4- is low spin due to the strong field ligand oxalate (ox). This results in 1 unpaired electron.
3. Calculate the spin-only magnetic moment (μs): μs = √n(n+2) BM, where n is the number of unpaired electrons. For [Co(ox)3]4-, n = 1, so μs = √1(1+2) BM = √3 BM ≈ 1.73 BM.
4. Apply the diamagnetic correction: Diamagnetic correction is usually a small value and depends on the ligands in the complex. Since you haven't provided a specific diamagnetic correction value, I can't give a precise numerical answer. However, you can look up the diamagnetic correction for oxalate (ox) ligand in a table or reference and subtract it from the spin-only magnetic moment to get the final μeff.
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