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Determine diamagnetic correction calculation for [co(ox) 3] 4-. Show equation
Accepted Answer
The diamagnetic correction calculation for [Co(ox)₃]⁴⁻ involves considering the contributions from both the cobalt(II) ion and the oxalate ligands. Here's a breakdown:
1. Cobalt(II) Ion (Co²⁺):
- Cobalt has an atomic number of 27, with an electron configuration of [Ar] 3d⁷ 4s². In the +2 oxidation state, it loses its 4s² electrons, leaving a d⁷ configuration.
- Diamagnetic correction for Co²⁺ is typically taken as ~12,000 cm⁻¹ based on empirical data.
2. Oxalate Ligands (ox):
- Each oxalate ligand (C₂O₄²⁻) has a diamagnetic correction, which can vary slightly depending on the specific complex.
- A common approximation is to use ~5,000 cm⁻¹ per oxalate ligand.
3. Total Diamagnetic Correction:
- The total diamagnetic correction for [Co(ox)₃]⁴⁻ is calculated by adding the contributions from the cobalt ion and the oxalate ligands.
- Therefore, the approximate diamagnetic correction is:
Diamagnetic Correction ≈ (12,000 cm⁻¹ for Co²⁺) + (3 × 5,000 cm⁻¹ for ox) = 27,000 cm⁻¹
Note: This is an approximation, and the actual diamagnetic correction may vary depending on the specific experimental conditions and theoretical calculations.
Equation:
Diamagnetic Correction ≈ Σ(Diamagnetic Correction of Metal Ion) + Σ(Diamagnetic Correction of Ligands)
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