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E. the number of atoms in 26.98 amu of Al: explain
Accepted Answer
The number of atoms in 26.98 amu of Al is 6.022 x 10^23 atoms.
Explanation:
1. Convert the mass of Al from amu to grams: 26.98 amu * (1 g / 6.022 x 10^23 amu) = 4.48 x 10^-23 g
2. Divide the mass of Al by the molar mass of Al to get the number of moles of Al: 4.48 x 10^-23 g / 26.98 g/mol = 1.66 x 10^-24 mol
3. Multiply the number of moles of Al by Avogadro's number to get the number of atoms of Al: 1.66 x 10^-24 mol * (6.022 x 10^23 atoms / mol) = 1 x 10^23 atoms
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