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Equation of state to calculate the pressure of 3.30 mol of hi at 475 k in a 6.00 l vessel using van der waals constants
Accepted Answer
The van der Waals equation of state is:
(P + a(n/V)²)(V - nb) = nRT
where:
P is the pressure
V is the volume
n is the number of moles
R is the ideal gas constant (0.0821 L atm/mol K)
T is the temperature
a and b are the van der Waals constants for the gas
For HI, a = 4.41 L² atm/mol² and b = 0.0449 L/mol.
Plugging in the values, we get:
(P + 4.41 (3.30/6.00)²)(6.00 - 0.0449
3.30) = 3.30
0.0821
475
Solving for P, we get:
P = 16.5 atm
Therefore, the pressure of 3.30 mol of HI at 475 K in a 6.00 L vessel using van der Waals constants is approximately 16.5 atm.
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