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Questions asked by users might not always be phrased in the clearest way.
The reaction provided is for the combustion of propane (C3H8), not ethane (C2H6). To solve this problem, we'll use the stoichiometry of the reaction and the heat of combustion:
1. Convert grams of CO2 to moles: 750 g CO2
(1 mol CO2 / 44.01 g CO2) = 17.04 mol CO2
2. Use the mole ratio from the balanced equation: 17.04 mol CO2
(2.04 x 10^3 kJ / 3 mol CO2) = 11,610 kJ
Therefore, 11,610 kJ of heat is produced when 750 grams of carbon dioxide gas are consumed in this reaction.