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Given 12 grams of copper, calculate the amount of nitrate that will be formed. cu+hno3= Cu(NO3)2+H2O+NO
Accepted Answer
To calculate the amount of nitrate formed, we need to balance the chemical equation and consider the stoichiometry. The balanced equation is:
3Cu + 8HNO₃ → 3Cu(NO₃)₂ + 4H₂O + 2NO
From this equation, we can see that 3 moles of copper react with 8 moles of nitric acid to produce 3 moles of copper(II) nitrate. To determine the amount of nitrate formed, you'll need to follow these steps:
1. Convert grams of copper to moles:
- Divide the mass of copper by its molar mass (63.55 g/mol).
2. Use the mole ratio from the balanced equation:
- The mole ratio of Cu to Cu(NO₃)₂ is 3:3 (or 1:1). This means for every mole of copper, you'll get one mole of copper(II) nitrate.
3. Calculate moles of copper(II) nitrate:
- Multiply the moles of copper by the mole ratio.
4. Convert moles of copper(II) nitrate to grams:
- Multiply the moles of copper(II) nitrate by its molar mass (187.56 g/mol).
This will give you the mass of copper(II) nitrate (Cu(NO₃)₂) formed from 12 grams of copper.
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