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Given 2al(s) + (3/2)o2(g) -> al2o3(s) deltahf = -1670 kj/mol for al2o3(s). Determine delath for the reaction 22o3(s) -> + 3o2(g)
Accepted Answer
The given reaction is: 2Al2O3(s) → 4Al(s) + 3O2(g)
The enthalpy change for the reaction can be calculated using the Hess's law:
ΔH = -ΔH(reverse reaction)
ΔH = -(-1670 kJ/mol)
ΔH = 1670 kJ/mol
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