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The ground state energy term for [Co(ox)3]4- is 4A2g. This can be determined using crystal field theory and considering the d-electron configuration of cobalt in the complex. Cobalt(II) has 7 d-electrons, and the octahedral complex with oxalate ligands (ox) as weak-field ligands results in a high-spin configuration. To calculate the magnetic moment, use the spin-only formula: μ = √n(n+2) BM, where n is the number of unpaired electrons. In this case, n = 3, and μ = √15 BM (Bohr magnetons).