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Ground state energy term of [co(ox)3] 4- and which theoretical magnetic moment would you use to calculate the magnetic moment and determine the diamagnetic correction calculation for magentic effective
Accepted Answer
The ground state energy term for [Co(ox)3]4- can be determined by considering the following:
1. Cobalt(II) ion: Co(II) has a d7 electronic configuration.
2. Oxalate ligand: Oxalate (ox) is a weak field ligand, causing small splitting of d-orbitals.
3. Octahedral complex: The complex is octahedral.
Considering these factors, the ground state energy term for [Co(ox)3]4- is 4T1g.
The theoretical magnetic moment used is the spin-only magnetic moment, calculated using the formula:
μs = √n(n+2) BM
Where 'n' is the number of unpaired electrons. For [Co(ox)3]4-, n = 3, giving a spin-only magnetic moment of 3.87 BM.
The diamagnetic correction is calculated by subtracting the diamagnetic contribution of the ligands and metal ions from the observed magnetic moment. This correction is typically small but can be significant for highly diamagnetic ligands or metals.
To determine the diamagnetic correction for [Co(ox)3]4-, you would need to consult tables of diamagnetic susceptibilities for the oxalate ligand and cobalt(II) ion.
Remember, the observed magnetic moment may differ slightly from the spin-only value due to factors like spin-orbit coupling, orbital contributions, and temperature effects.
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