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Assuming the density of the solution is 1 g/mL, the mass of NaOH in 500 mL of 0.1 M NaOH solution can be calculated as follows:
Mass of NaOH = Molarity × Volume of solution × Molecular weight of NaOH
Mass of NaOH = 0.1 mol/L × 500 mL × (22.99 g/mol + 16.00 g/mol + 1.01 g/mol)
Mass of NaOH = 0.1 mol/L × 500 mL × 40.00 g/mol
Mass of NaOH = 20.00 g
Therefore, there are 20.00 g of NaOH in 500 mL of 0.1 M NaOH solution.