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How to calculate the spin only moment for copper?

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Copper has an electronic configuration of [Ar] 3d^10 4s^1. Since it has only one unpaired electron, the spin-only magnetic moment can be calculated using the formula: μ = √n(n+2) BM, where n is the number of unpaired electrons. In this case, n = 1, so μ = √1(1+2) BM = √3 BM = 1.73 BM.

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