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How to calculate the spin only moment for Nickle

Accepted Answer

The spin-only magnetic moment for Nickel (Ni) can be calculated using the following formula:
μ = √n(n+2) BM
Where:

μ is the spin-only magnetic moment
n is the number of unpaired electrons
BM is the Bohr magneton (9.274 x 10^-24 J/T)
To determine the value of 'n' for Nickel, you need to consider its electronic configuration:
Ni: [Ar] 3d⁸ 4s²
In the ground state, Nickel has two unpaired electrons in its 3d orbitals. Therefore, n = 2.
Substituting this value into the formula, we get:
μ = √2(2+2) BM = √8 BM ≈ 2.83 BM
Therefore, the spin-only magnetic moment for Nickel is approximately 2.83 Bohr magnetons.

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