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I. Write an equation for the reaction between metaborate and water. ii. Write an equation between H₂O and one of the reaction products to show that metaborate is a diacidic base.
Accepted Answer
## i. Reaction between Metaborate and Water:
Metaborate (BO2-) reacts with water to form boric acid (H3BO3) and hydroxide ions (OH-):
BO2- (aq) + H2O (l) ⇌ H3BO3 (aq) + OH- (aq)
## ii. Metaborate as a Diacidic Base:
The boric acid (H3BO3) produced in the previous reaction can further react with water to form tetrahydroxyborate(III) ion [B(OH)4]-:
H3BO3 (aq) + 2H2O (l) ⇌ [B(OH)4]- (aq) + H3O+ (aq)
This reaction shows that metaborate (BO2-) can accept two protons (H+) from water molecules, indicating that it is a diacidic base.
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