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) Identify the ground state free ion term symbols and (b) the ground-state energy terms, in both octahedral and tetrahedral fields, for Mn2+
Accepted Answer
Mn2+ has a d5 electronic configuration. Here's how to determine the ground state term symbols and energy terms in octahedral and tetrahedral fields:
Octahedral Field:
Ground State Term Symbol: In a strong octahedral field, the d orbitals split into t2g and eg sets. Mn2+ has 5 d electrons, filling the t2g orbitals completely. This gives a maximum spin multiplicity (S=5/2) and zero orbital angular momentum (L=0). Therefore, the ground state term symbol is 6S.
Ground State Energy Term: Since L=0, there is no splitting due to the octahedral field. The ground state energy term is simply 6S.
Tetrahedral Field:
Ground State Term Symbol: The splitting pattern in a tetrahedral field is reversed, with the eg orbitals lower in energy. The five d electrons of Mn2+ will occupy the eg orbitals, resulting in a maximum spin multiplicity (S=5/2) and zero orbital angular momentum (L=0). Therefore, the ground state term symbol is 6S.
Ground State Energy Term: Similar to the octahedral case, the ground state energy term is 6S due to L=0.
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