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If 10 g of CaCl2 is required to saturate 100cm^3 of water at 30degreee celsius, calculate the solubility of CaCl2 at 30degree celsius in mol/dm^3
Accepted Answer
Calculating Solubility of CaCl2
Step 1: Convert Mass of CaCl2 to Moles
moles CaCl2 = 10 g CaCl2 * (1 mol CaCl2 / 110.98 g CaCl2)
= 0.0899 mol CaCl2
Step 2: Convert Volume of Water to Liters
volume water (liters) = 100 cm³ * (1 L / 1000 cm³)
= 0.1 L
Step 3: Calculate Solubility in mol/dm³
solubility = moles CaCl2 / volume water (liters)
solubility = 0.0899 mol CaCl2 / 0.1 L
= 0.899 mol/dm³
Step 1: Convert Mass of CaCl2 to Moles
moles CaCl2 = 10 g CaCl2 * (1 mol CaCl2 / 110.98 g CaCl2)
= 0.0899 mol CaCl2
Step 2: Convert Volume of Water to Liters
volume water (liters) = 100 cm³ * (1 L / 1000 cm³)
= 0.1 L
Step 3: Calculate Solubility in mol/dm³
solubility = moles CaCl2 / volume water (liters)
solubility = 0.0899 mol CaCl2 / 0.1 L
= 0.899 mol/dm³
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