Top topic this week
Back to FAQs
Related FAQs
Frequently Asked Question
Questions asked by users might not always be phrased in the clearest way.
If 1550 kj of heat are produced by the reaction below, how many grams of MnCl2 (mw = 126 g/mol) are consumed?rnmncl2 + 2hno3 → Mn(NO3)2 + 2hcl + 300 kj
Accepted Answer
The reaction produces 300 kJ of heat per mole of MnCl2 consumed. To produce 1550 kJ of heat, the following calculation can be used:
1550 kJ
(1 mol MnCl2 / 300 kJ) = 5.17 mol MnCl2
The mass of MnCl2 consumed can then be calculated:
5.17 mol MnCl2
(126 g/mol) = 652 g MnCl2
Articles you might like