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If C2H5OH + o2 → co + H2Ornrn95.1 grams of C2H5OH are reacted with 265 grams of O2, how many moles of co will be produced if the reaction proceeds with a 66% yield?
Accepted Answer
95.1 grams of C2H5OH is 2.13 moles of C2H5OH
265 grams of O2 is 8.28 moles of O2
From the balanced chemical equation:
C2H5OH + 3 O2 → 2 CO + 3 H2O
2.13 moles of C2H5OH react with (2.13 moles C2H5OH)(3 moles O2 / 1 mole C2H5OH) = 6.39 moles O2
Since only 8.28 moles of O2 are available, O2 is the limiting reactant.
(8.28 moles O2)(2 moles CO / 3 moles O2) = 5.52 moles CO
With a 66% yield, the actual moles of CO produced will be:
(5.52 moles CO)(0.66) = 3.65 moles CO
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