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If the cost of electricity required to deposit 3gram of al is 4naira, how much will it cost to deposit 12gram of copper
Accepted Answer
The cost of electricity required to deposit 12 grams of copper can be calculated using the following steps:
1. Convert the mass of copper to moles using its molar mass (63.5 g/mol):
12 g Cu * (1 mol Cu / 63.5 g Cu) = 0.189 mol Cu
2. Determine the number of moles of electrons required to deposit copper from its ionic form (Cu2+ to Cu):
2 mol e- / 1 mol Cu
3. Calculate the total charge required to deposit 0.189 mol of copper:
0.189 mol Cu * 2 mol e- / 1 mol Cu = 0.378 mol e-
4. Convert the charge to coulombs using the Faraday constant (96,485 C/mol e-):
0.378 mol e- * 96,485 C/mol e- = 36,462 C
5. Calculate the energy consumption using the formula: Energy (in joules) = Charge (in coulombs) * Voltage (in volts)
Assuming a voltage of 2 volts, the energy consumption is:
36,462 C * 2 V = 72,924 J
6. Convert the energy consumption to kilowatt-hours (kWh) to calculate the cost:
72,924 J * (1 kWh / 3,600,000 J) = 0.020 kWh
Assuming the cost of electricity is 4 naira per 3 grams of aluminum, the cost to deposit 12 grams of copper is:
0.020 kWh * (4 naira / 0.003 kg Al) * (12 g Cu / 3 g Al) = 32 naira
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