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If ZnS + o2 → ZnO + SO2rnrn246.92 grams of ZnS are reacted with 3.224 moles of O2, how many liters of SO2 will be produced at STP?
Accepted Answer
The balanced chemical equation is:
ZnS + 2O2 → ZnO + 2SO2
From the stoichiometry of the balanced equation, we can see that 1 mole of ZnS reacts with 2 moles of O2 to produce 2 moles of SO2.
Therefore, 246.92 grams of ZnS (which is 246.92 g / 97.44 g/mol = 2.536 mol) will react with 3.224 mol of O2 to produce 2.536 mol of SO2.
At STP, 1 mole of any gas occupies 22.4 liters.
Therefore, 2.536 mol of SO2 will occupy 2.536 mol * 22.4 L/mol = 56.66 L.
Therefore, 56.66 liters of SO2 will be produced at STP.
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