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In a separate reaction, 0.775g of zinc powder was reacted with 8.5 ml of hydrochloricrnacid solution. The hydrochloric acid solution has a density of 1.09 g/ml. Use thisrninformation to answer the questions below.rnrnwhat is the percent yield of zinc chloride for this reaction if 1.230 g of zincrnchloride were actually obtained? Show work.
Accepted Answer
The balanced chemical equation for the reaction between zinc and hydrochloric acid is:
Zn + 2HCl → ZnCl2 + H2
From the equation, we can see that 1 mole of zinc reacts with 2 moles of hydrochloric acid to produce 1 mole of zinc chloride.
Step 1: Calculate the moles of zinc used.
moles of Zn = mass of Zn / molar mass of Zn
= 0.775 g / 65.38 g/mol
= 0.0118 mol
Step 2: Calculate the moles of hydrochloric acid used.
moles of HCl = (density of HCl solution) * (volume of HCl solution) * (molarity of HCl solution)
= (1.09 g/mL) * (8.5 mL) * (1 mol/L) / (36.46 g/mol)
= 0.0256 mol
Step 3: Determine the limiting reactant.
To determine the limiting reactant, we compare the moles of each reactant to the stoichiometric ratio in the balanced equation.
Zn: 0.0118 mol / 1 = 0.0118
HCl: 0.0256 mol / 2 = 0.0128
Since 0.0118
Step 4: Calculate the theoretical yield of zinc chloride.
theoretical yield of ZnCl2 = moles of Zn * molar mass of ZnCl2
= 0.0118 mol * 136.29 g/mol
= 1.611 g
Step 5: Calculate the percent yield of zinc chloride.
percent yield = (actual yield / theoretical yield) * 100%
= (1.230 g / 1.611 g) * 100%
= 76.32%
Therefore, the percent yield of zinc chloride for this reaction is 76.32%.
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