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Is Na2[Co(SCN)4] spin allowed
Accepted Answer
To determine if the transition in Na2[Co(SCN)4] is spin-allowed, we need to consider the electronic configuration of the cobalt(II) ion and the nature of the ligand field.
Co(II) has a d7 electronic configuration. In a tetrahedral complex like Na2[Co(SCN)4], the SCN- ligand is a weak field ligand, resulting in a high-spin configuration.
Therefore, the transition is likely spin-allowed, as the ground state and excited state both have the same spin multiplicity (S = 3/2).
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